Use Community_Assist --joins Select * From Employee --inner join Select PersonLastName, PersonFirstName, PersonEmail, EmployeeHireDate, EmployeeAnnualSalary From Person inner join Employee On Person.PersonKey = Employee.PersonKey --just join inner optional and aliased tables Select p.PersonKey, PersonLastName, PersonFirstName, PersonEmail, EmployeeHireDate, EmployeeAnnualSalary From Person p join Employee e On p.PersonKey = e.PersonKey Select * from EmployeePosition Select * from Position --4 table inner join Select PersonLastName, PersonFirstName, PersonEmail, EmployeeHireDate, PositionName, EmployeeAnnualSalary From Person inner Join Employee on Person.PersonKey=Employee.PersonKey inner join EmployeePosition on Employee.EmployeeKey=EmployeePosition.EmployeeKey inner join Position on Position.PositionKey=EmployeePosition.PositionKey Select PersonLastName, PersonFirstName, PersonEmail, EmployeeHireDate, PositionName, EmployeeAnnualSalary From Person, Employee, EmployeePosition, Position Where Person.PersonKey=Employee.PersonKey And Employee.EmployeeKey = EmployeePosition.EmployeeKey And Position.PositionKey=EmployeePosition.EmployeeKey --leave out position creates an accidental cross join Select PersonLastName, PersonFirstName, PersonEmail, EmployeeHireDate, PositionName, EmployeeAnnualSalary From Person, Employee, EmployeePosition, Position Where Person.PersonKey=Employee.PersonKey And Position.PositionKey=EmployeePosition.EmployeeKey --cross join Select PersonLastName, PersonFirstName, PersonEmail, EmployeeHireDate From Person, Employee --explicit cross join Select PersonLastName, PersonFirstName, PersonEmail, EmployeeHireDate From Person Cross join Employee --outer join --an outer join returns all the records from one table --and only matching records from the other --the left table is the first table named --the right table is the second table named Select GrantTypeName, GrantRequest.GrantTypeKey From GrantType left outer join GrantRequest On GrantType.GrantTypeKey = GrantRequest.GrantTypeKey Where GrantRequest.GrantTypeKey is null Select GrantTypeName, format(avg(GrantRequestAmount),'$#,##0.00') Average From GrantType inner join GrantRequest on GrantType.GrantTypeKey=GrantRequest.GrantTypeKey Group by GrantTypeName having avg(GrantRequestAmount)>400
Monday, April 18, 2016
Joins
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