Here are the examples from class today. All use the MagazineSubscription database.
/******************************
This document provides examples
of aggregate functions, that is
fuctions that operate on more than
one row at a time
*******************************/
use MagazineSubscription
--the basic functions
SELECT Count(*) "Total Subscriptions"
from Subscription
Select Max(SubscriptionPrice) as "Most"
From MagazineDetail
Select Min(SubscriptionPrice) as Least
From MagazineDetail
--not a particularly meaninful number
Select Sum(SubscriptionPrice) as "so?"
From MagazineDetail
--more meaningful
Select AVG(SubscriptionPrice) as "Average Price"
From MagazineDetail
--With distinct (eliminates duplicates before
--computing average
Select AVG(Distinct SubscriptionPrice) as "Average Price"
From MagazineDetail
--more meaningful yet
Select SubscriptTypeID, AvG(SubscriptionPrice) "Average Price"
From MagazineDetail
Group by SubscripttypeID
Order by "Average Price" DESC
--using the having clause
Select SubscriptTypeID, AvG(SubscriptionPrice) "Average Price"
From MagazineDetail
Group by SubscripttypeID
having Avg(SubscriptionPrice) > 50
Order by "Average Price" DESC
--Count how many subscriptions each customer who has more than 2 has
Select CustID, Count(SubscriptionID)"Total Subscriptions"
From Subscription
Group by CustID
having Count(SubscriptionID) > 2
Further note: The last assignment in Assignment3 on Aggregate functions is not doable without subqueries which I have not shown you yet. Don't worry about it. I will show you how to do it Wednesday. (Monday is a Holiday)
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